(x^2-7)(2x^2-17x+8)=0

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Solution for (x^2-7)(2x^2-17x+8)=0 equation: 


Simplifying
(x2 + -7)(2x2 + -17x + 8) = 0

Reorder the terms:
(-7 + x2)(2x2 + -17x + 8) = 0

Reorder the terms:
(-7 + x2)(8 + -17x + 2x2) = 0

Multiply (-7 + x2) * (8 + -17x + 2x2)
(-7(8 + -17x + 2x2) + x2(8 + -17x + 2x2)) = 0
((8 * -7 + -17x * -7 + 2x2 * -7) + x2(8 + -17x + 2x2)) = 0
((-56 + 119x + -14x2) + x2(8 + -17x + 2x2)) = 0
(-56 + 119x + -14x2 + (8 * x2 + -17x * x2 + 2x2 * x2)) = 0
(-56 + 119x + -14x2 + (8x2 + -17x3 + 2x4)) = 0

Combine like terms: -14x2 + 8x2 = -6x2
(-56 + 119x + -6x2 + -17x3 + 2x4) = 0

Solving
-56 + 119x + -6x2 + -17x3 + 2x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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